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Cleo Vane.Salon Growth

Four worked models · every assumption on the page

Not a client result. Arithmetic.

Four changes owners ask me about, modeled from stated assumptions so you can see where the money actually moves — including the one where it moves the wrong way.

What these are and are not. Every number below is invented to make the arithmetic legible. None of it is a benchmark, an industry average, a client outcome or a forecast for your salon. The useful part is the shape of the calculation and the list of things it leaves out. Re-run each one with your own figures from the chair-hour calculator and your own booking data.
01

Worked model: raising the average ticket by one addition

Assumptions

Starting arithmetic

Weekly revenue30 × $68$2,040
Annual revenue$2,040 × 46$93,840

Change modeled

The addition is offered by name at every consultation, with a price, before the service starts.

New arithmetic

Additions sold per week30 × 0.257.5
Added revenue per week7.5 × $12$90
New weekly revenue$2,040 + $90$2,130
New average ticket$2,130 ÷ 30$71
New annual revenue$2,130 × 46$97,980
Difference$97,980 − $93,840$4,140

Costs and risks omitted

Questions before applying it

02

Worked model: halving the no-show rate

Assumptions

Starting arithmetic

Missed per week30 × 6%1.8
Revenue not earned, weekly1.8 × $68$122.40
Revenue not earned, annually$122.40 × 46$5,630
Cost the empty hour still carries1.8 × $52$93.60

New arithmetic

Missed per week30 × 3%0.9
Revenue not earned, weekly0.9 × $68$61.20
Recovered per year$61.20 × 46$2,815

Costs and risks omitted

Questions before applying it

03

Worked model: the thing you give away

Assumptions

Starting arithmetic

Unpaid chair time, weekly12 × 15 min3 hours
Cost of that time3 × $52$156
Product12 × $2$24
Carried by the salon, weekly$156 + $24$180
Carried by the salon, annually$180 × 46$8,280

Change modeled

Another salon’s work is removed as a priced 20-minute service. Your own work is folded into a named Reset appointment. New sets are booked with the extra 15 minutes actually in the diary, and priced for it.

New arithmetic

Charged removals4 × $18$72
15 minutes priced into the set0.25 × $52$13
Applied to the remaining sets8 × $13$104
Recovered per year($72 + $104) × 46$8,096

Costs and risks omitted

Questions before applying it

04

Worked model: a controlled four-day week

This is the one owners hope I will confirm. On these assumptions, it does not confirm.

Assumptions

Starting arithmetic

Weekly revenue30 × $68$2,040
Less fixed costs−$1,450$590

New arithmetic

New ticket$68 × 1.08$73.44
Appointments kept30 − 10%27
Weekly revenue27 × $73.44$1,982.88
Less fixed costs−$1,450$532.88
Difference$532.88 − $590−$57.12

Fixed costs do not take a day off. That is the whole model in one sentence.

What would have to be true instead

Keep all 30 appointments30 × $73.44 − $1,450$753.20
Appointments needed just to stand still$2,040 ÷ $73.4427.8 → 28

So the four-day week pays for itself here only if you keep at least 28 of your 30 appointments — 93% — inside a shorter, denser week. That is a retention question, not a lifestyle question, and it is answerable before you announce anything.

Costs and risks omitted

Questions before applying it

Run one with your own numbers

Model I am re-running

My chair-hour figure

My average ticket

Starting arithmetic

New arithmetic

What I left out, and would need to check before doing it